ΔT=25−14.025=10.975∘C\Delta T = 25 - 14.025 = 10.975^\circ CΔT=25−14.025=10.975∘C
Increase 1% per °C:
=10.975%= 10.975\%=10.975%
(iii) Gradient correction Increase 20% per 1% gradient:
=0.5×20=10%= 0.5 \times 20 = 10\%=0.5×20=10%
(iv) Corrected runway length (take-off governs)
L=2500×(1+0.035+0.10975+0.10)L = 2500 \times (1+0.035+0.10975+0.10)L=2500×(1+0.035+0.10975+0.10) L≈3110 m (approx.)L \approx \boxed{3110 \text{ m (approx.)}}L≈3110 m (approx.)
Q4. Harbour – Design Factors
Harbour: A sheltered water area for ships to anchor safely.
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