(SEM V) THEORY EXAMINATION 2024-25 STRUCTURAL ANALYSIS
Subject Code: BCE502
Maximum Marks: 70
Time: 3 Hours
Paper ID: 310458
Question Paper Overview
SECTION A (2 × 7 = 14 Marks)
(Short theoretical questions — definitions, principles, and basic concepts)
a. Classify structures based on stability.
b. Where should loads be applied on a pin-jointed truss?
c. Give the classification of trusses.
d. List the assumptions made while finding forces in a truss.
e. What is the use of Maxwell’s Reciprocal Theorem?
f. State the advantages of Influence Line Diagrams (ILDs).
g. Explain the principle of Eddy’s Theorem.
SECTION B (Attempt any three × 7 = 21 Marks)
(Medium-length derivation or application-based problems)
a. Determine the degree of indeterminacy of the truss shown in figure.
b. Explain simple trusses (with sketch) that are stable in form independent of support conditions.
c. A continuous beam ABC of equal spans l undergoes settlement:
Support B sinks by δ₁, and support C sinks by δ₂.
Find reactions using the strain energy method.
d. A UDL of 15 kN/m (3 m long) crosses a 10 m span girder — find the maximum shear force (S.F.) and bending moment (B.M.) at a section 4 m from the left support.
e. Formulate the equations for a three-hinged parabolic arch and a three-hinged circular arch.
SECTION C (Attempt one part from each question × 7 = 35 Marks)
Q3
(a) Define static indeterminacy and give at least two examples in trusses.
OR
(b) A cable of 100 m span with ends 8 m above its lowest point carries a UDL of 10 kN/m.
Find horizontal and vertical reactions at supports and the length of cable.
Q4
(a) For a Warren-type cantilever truss, determine member forces using the method of tension coefficients.
OR
(b) State the conditions for zero-force members in a truss.
Q5
(a) A simply supported beam (6 m) has a 45 kN load at 2 m from left support.
Find deflection under the load using unit load method.
Take E = 200×10⁶ kN/m² and I = 14×10⁻⁶ m⁴.
OR
(b) A beam ABCD (30 m) is simply supported at A and D, with I-values:
I₁ = I (AB = 10 m),
I₂ = 3I (BC = 10 m),
I₃ = 2I (CD = 10 m).
Loads: 150 kN at B, 300 kN at C.
Using Conjugate Beam Method, determine slopes and deflections at A, B, C, D.
Given: E = 200 kN/mm², I = 2×10¹⁰ mm⁴.
Q6
(a) Explain Müller–Breslau’s Principle and verify with an example.
OR
(b) Draw influence line diagrams (ILDs) for S.F. and B.M. at a section 3 m from left end of a 12 m simply supported beam, and determine max S.F. and max B.M. due to a 5 m UDL of 2 kN/m.
Q7
(a) Define normal thrust and radial shear force for three-hinged arches. Derive expressions for both.
OR
(b) A three-hinged parabolic arch (span = 20 m, rise = 4 m) carries UDL = 20 kN/m on half span.
Find maximum bending moment for the arch.
Key Topics for Revision
1. Classification of Structures
Based on stability:
Stable, Unstable, Determinate, Indeterminate.
Static determinacy condition:
- Ds=r+m−2jD_s = r + m - 2jDs=r+m−2j
where rrr = reactions, mmm = members, jjj = joints.
2. Trusses
Loads in truss: Applied only at joints (assumed pin-connected).
Types: Simple, Compound, Complex.
Assumptions:
Members are pin-jointed.
Loads act only at joints.
Self-weight neglected.
Members carry only axial force (tension or compression).
Zero-force members:
At a joint with two non-collinear members & no load, both are zero-force.
At a joint with three members and two are collinear, the third is zero-force.
3. Maxwell’s Reciprocal Theorem
States that:
- δAB=δBA\delta_{AB} = \delta_{BA}δAB=δBA
Deflection at point A due to unit load at B = deflection at B due to unit load at A.
Used in flexibility methods.
4. Influence Line Diagrams (ILDs)
Show variation of internal forces (S.F., B.M., reaction) at a specific point as a unit load moves across the structure.
Applications: Analysis of moving loads, bridges, cranes, etc.
Advantages:
Determine max values under any moving load.
Essential for bridge and railway design.
5. Theorems of Structural Analysis
Eddy’s Theorem: Relation between strain energy and deflection.
Müller–Breslau’s Principle:
Shape of ILD for a function = deflected shape of structure when that function is given a unit displacement.
6. Bending and Deflection Methods
Unit Load Method:
- δ=∫MmEIdx\delta = \int \frac{M m}{EI} dxδ=∫EIMmdx
where MMM = moment due to actual load, mmm = moment due to unit load.
Conjugate Beam Method: Converts real beam → imaginary beam to find slopes and deflections.
7. Arches
Normal Thrust (N): Component of arch reaction along its axis.
Radial Shear (Q): Component perpendicular to axis.
For Parabolic Arch:
- y=4hL2x(L−x)y = \frac{4h}{L^2}x(L-x)y=L24hx(L−x)
For Circular Arch:
- R=L2+4h28hR = \frac{L^2 + 4h^2}{8h}R=8hL2+4h2
8. Cables
Parabolic cable carrying UDL (w per unit length):
Horizontal thrust:
- H=wL28hH = \frac{wL^2}{8h}H=8hwL2
Maximum tension:
- Tmax=H2+(wL/2)2T_{max} = \sqrt{H^2 + (wL/2)^2}Tmax=H2+(wL/2)2
Length of cable:
- l=L+8h23Ll = L + \frac{8h^2}{3L}l=L+3L8h2
9. Indeterminacy
Static Indeterminacy (Dₛ):
- Ds=r+m−2jDₛ = r + m - 2jDs=r+m−2j
Kinematic Indeterminacy (Dₖ): Number of independent joint displacements.
Examples: Fixed beam, continuous beam, redundant truss.
10. Important Formulas for Quick Revision
| Concept | Formula |
|---|---|
| Shear force at a section due to UDL | V=w(l−x)V = w(l - x)V=w(l−x) |
| Bending moment at a section | M=wx(l−x)/2M = wx(l - x)/2M=wx(l−x)/2 |
| Deflection due to point load (centre) | δ=WL348EI\delta = \frac{WL^3}{48EI}δ=48EIWL3 |
| Slope at supports (simply supported beam) | θ=WL216EI\theta = \frac{WL^2}{16EI}θ=16EIWL2 |
| ILD ordinates for S.S. beam | y=xLy = \frac{x}{L}y=Lx and 1−xL1 - \frac{x}{L}1−Lx |
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